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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Feb 2008 20:34:16 IST
Accepted Answer [?]
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me thinks the answer is 1 taking 1/81^n common 1/81^n(1-(10/81)2nC1+(10^2)2nC2.........
=1/(81)^n (1-10)^2n =1/(81)^n * 9^2n
=1
if any mistake plz do point out!!
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this reply: 5 points
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