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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: Binomial theorem
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abhijeet_0201 (756)

Blazing goIITian

Olaaa!! Perrrfect answer. 120  [198 rates]

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me thinks the answer is 1
taking 1/81^n common
1/81^n(1-(10/81)2nC1+(10^2)2nC2.........

=1/(81)^n (1-10)^2n
=1/(81)^n * 9^2n

=1

if any mistake plz do point out!!
 this reply: 5 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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