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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Feb 2008 12:07:21 IST
Accepted Answer [?]
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v=10/9-5w.....v-velocity of the person wrt ground,w=angular velocity of the disc
W=angular velocity of the person about axis of rotataion=v/5=(10/9-5w)/5
now the conservation of angular momentum
L(f)=L(i)
taking clockwise as positive
mr^2*W-MR^2w/2=0
60*25*(2/9-w)-100*100*w/2=0
solve for w
w=2/39 rad/s=2*60/(39*3.14)=0.489 rev/min
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