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[Post New]5 Feb 2008 12:04:29 IST
    Subject: Re:f(x^n) is divisible by (x-1)...what is it also divisible by?
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akhil_o (2709)

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Heres the solution...
f(1n)=0 by factor theorem
putting xn=y
f(xn)=f(y) with f(1)=0
=> y-1 is a factor of f(y)
=> (xn-1)is a factor of f(xn)
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