1.There are 5B and 6G.
No boy sits together.leave the boys n 1st arrange the girls.they can b arranged in 6! ways.There will be (n+1)!ways for boys to sit..i.e here 5B can be arranged in 7p5 ways which is n(E)
n(S)=6+5=11..which implies 11!
p(E)=6!*7P5/11!
Moderation Team
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