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konichiwa2x (2342)

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Olaaa!! Perrrfect answer. 440  [511 rates]

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Well this is not a very different method, but anyway...
In general if , are the roots of a polynomial of degree n, then
this is very easy to see: let then
now differentiate with respect to x to get the result. so, for example, if ,
then , and thus
 
ps. you can do this by another method, but its pretty tedious. You can look at the case e.g n=3 or n=4 and then generalize.Clear the denominators, simplify, and group on the left. using that sums of roots, products of pairs of roots, etc are -1,+1, -1 , + 1 etc from coefficients of P(x) combined with P(1) = n+1, you can prove it.

Guide to latex:
http://www.goiit.com/posts/list/community-shelf-a-guide-to-latex-48056.htm

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