Well this is not a very different method, but anyway...
In general if
, are the roots of a polynomial
of degree n, then
this is very easy to see: let
then
now differentiate with respect to x to get the result. so, for example, if
,
then
, and
thus 
ps. you can do this by another method, but its pretty tedious. You can look at the case e.g n=3 or n=4 and then generalize.Clear the denominators, simplify, and group on the left. using that sums of roots, products of pairs of roots, etc are -1,+1, -1 , + 1 etc from coefficients of P(x) combined with P(1) = n+1, you can prove it.