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![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Feb 2008 13:35:57 IST
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dat's correct ramayani------ F*4/3>Mg
 F>3/4 Mg
now this force acts on the opposite side on d bullet.
 -3/4Mg=ma....a is the deceleration of the bullet once it enters the block.
v(f)=0;
v(f)=v(i)+at
v(f)=0;
-3/4 Mgt/m=v....but problem is we dont know the time
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