IIT JEE , AIEEE Forum - Physics , Mechanics

atavistic

Answer is M/m[3ga(^{[ 2]}

2 -1)]^1/2

I tried CoM and energy approach.But I am not getting the answer,I am getting a 2 instead of the 3 there.

What i did was initial height of CoM(y)= a,since M>>>m so final also a,now i rotated the cube so that its base makes angle of 45 with the horizontal.This way the CoM goes to a height ^{[2 ]}

2a.So change in GPE = (M+m)ga(^{[ 2]}

2 - 1) this should be equal to KE which I used as 1/2mv^2...maybe u have to use rotational KE but i dont know inertia about that axis.Plz help someone.

The problem is I havent used 4a/3 anywhere :S

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