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![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Feb 2008 18:31:37 IST
Accepted Answer [?]
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when the block is shifted by a distance x along the spring c it is acted upon by 3 forces of a b and c
for a restoring force(f1)=kx
for b f2=kx cos45
for c f3=kx cos 45
the resultant of f2 and f3 is along f1
R2,3=underroot(k^2x^2cos^45+k^2x^2cos^45 +o)=kx
[f2 and f3 are perpendicular to each other]
therefore total restoring force=kx+kx=2kx
which is proportional to x, therefore s.h.m
now
2kx=mw^2x
w^2=2k/m
T=2pie /underroot(w^2)
=2pie underroot(m/2k)
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