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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Feb 2008 16:46:40 IST
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OKAY SO HERE'S THE SOL
I CANT MAKE THE DIAG(THEY HAVE CONSIRED SHM AS REFLEC ON CIRCLE)
SO ILL JUST TYPE THE SOL
the phase diff b/w the particles
phi=pi/6 +pi/4 =5pi/12
th will collide when the perpendicular s drawn on the the diameter coincide.this will happen when any of the particle rotates an angle
theta =phi +phi' (on the figure they ,ve shown phi''=5pi/24 (dont know how)
=5pi/12 + 5pi/24=5pi/8
or wt =5pi/8
t= 5pi/8 x T/2pi
=5T/16'
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