sign up I login
 advanced
refer a friend - earn nickels!!

Ask & Discuss Questions with Community & Experts

Moderation Team
Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: Please explain this to me........
Forum Index -> Modern Physics -> View Full Question like the article? email it to a friend.  
Author Message
bhavanawannastudy (67)

Cool goIITian

Olaaa!! Perrrfect answer. 11  [17 rates]

bhavanawannastudy's Avatar

total posts: 67    
offline Offline
lets say we found the accurate momentum of an electron, say p that is there is no uncertainity in this value and hence p =0. now we have =h/p , since p is definite hence the wavelengh will also b definite(we r considering the wave nature of electron) now this wave will extend all over space which means we cannot determine the position of electron with accuracy it can b at any point in the space and hence is uncertain. x=infinity. since generally the wavelenght associated wid the electron is not single hence from debroglie relation there is also some uncertainity in momentum,  and x is not equal to infinity. the relation established between the two is xp h/2
 this reply: 5 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
You have to be logged on to rate
  
 

Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Narayana - Kota , Delhi , Others
Brilliant Tutorials - Class , Crash
Aakash Institute - Medical , Engg
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya