1st step : count the no. of valence electrons[ V ]
2nd step : now divide V by 8 ,if V >8
or
divide V by 2 ,if V <=8 -[1]
if the remainder is still not zero then
again divide it by 2, - [2]
therefore the final value = quotient in 1+ quotient in 2
as shown in the example
3rd step : compare the above obtained value with the table given below :-
sp - 2
sp2 - 3
sp3 - 4
sp3d - 5
sp3d2 - 6
sp3d3 - 7
ex:- for c2h6
step 1 - 2[4 ] + 6[1] = 4+6=10
step 2 - as 14>8
14/8, quotient=1 as remainder = 6 which is not equal to zero
therefore 6 / 2 quotient=3
therefore final value=1+3=4
comparing with the table given above
the hybridisation is sp3.
note - this is not applicable to all compounds
E-Store
shortcut way to find hybridisation
