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rooney (894)

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Olaaa!! Perrrfect answer. 152  bad job dude!! I dont approve of this answer! 1  [221 rates]

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I am very confused here.

1st of all..ques 5 seems to have been cancelled because of the typo. And tarinbansal tried ques 1,2,3,4,6. each of which are valid. So, he cant get 40. Either he gets 50 or less than 40.

2nd ly....answer given to ques 6 is not agreed upon.

It is clearly given that mass is negligible and therefore, rotational energy will not be considered. So,
1/2 mv2 + 1/2 kx2= c
v = dx/dt

Differentiating 1st eq with respect to x,
=> 1/2m x 2v dv/dx + kx=0
=> mvdv/dx = -kx
=> mdv/dt= -kx
=> md2x/dt2= -kx
=> d2x/dt2= -(k/m)x

Comparing -(k/m)x = - 2x,
= root(k/m). Hence, (a)

Karthik...jaldi clarify kar yaar. Please. Mera dimag kharab ho raha hai.  


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