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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Feb 2008 03:39:15 IST
Accepted Answer [?]
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1) since +ve plate of 1st capacitor is connected to - ve plate of second capacitor
they are in series
eq capacitanceC'=C1C2/C1+C2
=5C/3
now since they are in series
eq pot diff V'=V1+V2
V'=2V+V=3V
initial energy=( C1V1^2)/2 + (C2V2^2)/2
(8+1)/2 CV^2=4.5CV^2
final energy= (C'V'^2)/2
=3CV^2
so loss in energy=(4.5-3)CV^2
=1.5CV^2
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