4) Let the centre of the bigger disc be the origin
2R = Radius of bigger disc
R = Radius of smaller disc
m1= 
R^2T
m2 =(2R)^2T (where T = thickness of two disc ,=density of the discs)
Position if centre of mass
=[ m1x1+m2x2/(m1+m2) , m1y1+m2y2/(m1+m2)]
x1=R ; y1=0
x2=0 ; y2= 0
keeping value of m1 and m2
= [ 
R^2TR/(R^2TR + (2R)^2T) , 0 ] On solving
= [R/5,0]
Moderation Team
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