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mukulss (493)

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Olaaa!! Perrrfect answer. 75  [134 rates]

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M2:[very simple and very food too]

by making use of an implicit relation:

see in this type:

use:

dx/dy = [cos(a+y)][-siny]+ [cosy][sin(a+y)]
--------------------------------------------
[cos2(a+y)]
see now:

dx/dy = sina / [cos(a+y)]^2

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