|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Feb 2008 16:46:48 IST
|
|
|
M2:[very simple and very food too]
by making use of an implicit relation:
see in this type:
use:
dx/dy = [cos(a+y)][-siny]+ [cosy][sin(a+y)] -------------------------------------------- [cos2(a+y)] see now:
dx/dy = sina / [cos(a+y)]^2
|
this word is so small that it is a foolishness to hate anyone.
so, we love all. |
this reply: 7 points
(with 1 
in 2 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|