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raulrag009 (1223)

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Olaaa!! Perrrfect answer. 205  [304 rates]

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Consider the parabola y2=4ax
 
Let PQ be latus rectum
 
Let AB be a focal chord
Let  FB=c  FA=c2
 
Let the coordinates of A and B be (at12,2at1) and (a/t12 , -2a/t1)
                                                                     As t1t2=-1
F=(a,0)
 
NOW
 
c1=a[1+t12]/t12             and c2 = a[1+t12]
c1+c2 = a[1+t12]/t12     +  a[1+t12]
 
c1c2 =a2/t12 [1+t12]2
 
divide both
c1c2/c1 +c2   =  a
 
multiply by 2 on both sides
 
2c1c2/c1+c2  =2a
 
thus
 
proved
 

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