Consider the parabola y2=4ax
Let PQ be latus rectum
Let AB be a focal chord
Let FB=c1 FA=c2
Let the coordinates of A and B be (at12,2at1) and (a/t12 , -2a/t1)
As t1t2=-1
F=(a,0)
NOW
c1=a[1+t12]/t12 and c2 = a[1+t12]
c1+c2 = a[1+t12]/t12 + a[1+t12]
c1c2 =a2/t12 [1+t12]2
divide both
c1c2/c1 +c2 = a
multiply by 2 on both sides
2c1c2/c1+c2 =2a
thus
proved