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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Feb 2008 00:59:25 IST
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T_T is right.
The answer is 0 and can be got by using pure common sense. It is quite obvious that a point chosen at random from a sphere cannot be exactly on the surface.
@hsbhatt
There is no density involved here.
the probability = favourable volume / total volume.
Favourable volume =area x height= 4 r2 dr
But since dr is infinitely small , this quantity will be 0. dr can be assumed to be non-zero only when we are using integration.
Total volume = 4R3/3.
Since this is finite , the final answer will be 0.
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