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akhil_o (2709)

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Olaaa!! Perrrfect answer. 435  [702 rates]

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if u mean integration of tan^3 x
 
[ ][ ] tan3x
=tan x(sec2x-1)
=tanx sec2x-tan x dx
tan x=t,dt=sec2xdx
tdt-tanx dx
=tan2x/2 -log |sec x|

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