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| Forum Index -> Integral Calculus -> View Full Question |
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I =  ex sin2x dx = -ex cos2x/2 + ex cos2x/2 dx (Integ by parts) =-ex cos2x/2 + ex sin2x/4 - 1/4 ex sin2x dx =-ex cos2x/2 + ex sin2x/4 - 1/4I Hence 5I/4 = -ex cos2x/2 + ex sin2x/4 or I = 4/5 (-ex cos2x/2 + ex sin2x/4) |
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