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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Feb 2008 18:29:07 IST
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dq=du+dw dq=0 for adibiatic 0=du+dw
d(pv)=nrt pdv+vdp = nrdt ndt = (pdv + vdp)/r
since du = nCvdt dw = pdv 0 = nCvdt + pdv 0 = Cv[(pdv+vdp)/r]+pdv pdv [1+Cv/r] = -CvVdp/r pdv Cp/r = -Cv Vdp/r by intigrating Cp logV = -Cv logP + logk Cp Cv logV + logP = log k
P^Cv * V^Cp = k
Cp/Cv P^ = k by comparing with P^Y=c Y=cp/cv
i think it is useful for u
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if u live to be a hundred
i want to live to be hundred minus 1 day
so i never have to live without u
.
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