rakhi here is the elaborated way till 3rd diagram u can compute logically after that consider this y1 = A Sin(1t) y2 = A Sin(2t + ) y1 = y2 Sin (2t/T) = Sin (2t/4T + /2) ......as second pendulum has initial phase /2 solving u get t = T/3 in T sec 1st pendulum completes 1oscillation so in T/3 it covers 1/3 oscillation but in 1st , 2nd 3rd diagrams it has already covered 1 oscillation so total oscillations = 1 + 1/3 = 4/3
nudge me for further doubts
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1t)
)
t/T) = Sin (2
