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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Feb 2008 13:00:18 IST
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@raulrag
I = - ? et dt /t2
by parts
I = - [et/t2 + ?et/t dt]
kaise?????? u're have to take derivative of first function dude
@deedee
yes integration of e^x is e^x
but here it's e^1/x dx
if it would have been e^1/x d1/x then ans would have been e^1/x + c
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