|
|
|
|
|
Discussion Response Post to:
logi=
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Feb 2008 20:33:32 IST
|
|
|
we can write
i = cos (pi/2) + i sin ( pi/2 ) = ei(pi/2)
therefore
log i = loge ( ei(pi/2) )
= i (pi/2)
cheeeeerrsssssssss!!!!!!!!
|
............................................................................................................................................................................................
There's Light at the end of every Tunnel, so KEEP MOVING....
Best of luck to all my mates....
............................................................................................................................................................................................
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|