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[Post New]20 Feb 2008 13:08:37 IST
    Subject: Re:integrate
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raulrag009 (1223)

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Olaaa!! Perrrfect answer. 205  [304 rates]
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Multiply by sec2x in numerator and denominator
 
I =sec^2xdx / (1+tan2x)(1+2tan2x)
 
Put tanx=t
      sec^2xdx=dt
I = dt/(1+t2)(1+2t2)
 
Let
 
1/(1+t2)(1+2t2)  =  At+B/1+t^2   +   Ct+D/1+2t^2 
 
u can solve further by comparing
 
Ans is
tan-1(2tanx)  -  tan-1(tanx) +C
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