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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Feb 2008 23:36:30 IST
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c for the curve the diff eqn comes out to be
dy/ dx = a-2x/2y
replace dy/dx by -dx/dy....and solve
u get
dx/2x-a = dy/2y
integrating both sides ull get
1/2 log( 2x - a)+ log c = 1/2 log y
= C(2x-a) = y
this is the orthogonal trajectory for the given curve ...
hope u have understood...nudge me if u have any doubt
rate if useful
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