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chetan_kp (283)

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Olaaa!! Perrrfect answer. 45  [74 rates]

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1)Two moles of monoatomic gas is mixed with three moles of diatomic gas. The molar specific heat of the mixture at constant volume is ??
1 of monoatomic gas = (f+2)/f = (3+2)/3 = 5/3

2 of diatomic gas = (5+2)/5 = 7/5


= [n1 1 + n22] / (n1+ n2)
   = 1.506
Cv = R/ ( -1)
Cv = 16.43

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