just giving a easy way for calculating this, hope its useful 2M + (x/2)O2 M2OX 5gm 9.44gm clearly increase in mass due to addition of oxygen = (9.44-5)= 4.44gm 1 eq. mass of any metal always reacts with 8gm of oxygen in this case 5gm of metal reacts with 4.44 gm of oxygen so mass of metal required to react with 8gm of oxygen = eq. mass of oxygen = (5*8)/4.44 = 9.009gm
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M2OX 
