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Discussion Response Post to:
who wants to be in iit
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25 Feb 2007 19:25:57 IST
Subject:
who wants to be in iit
01725074660vir
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Hi i think the sol. is
Let R1 & R2 be the 2 resistances . thermal power generated in the circuit is
P =i^2( R1R2/R1+R2)
in parallel combination,thermal power will be minimum if:
i^2 (R1R2 / R1+R2) < i^2 (R1 + R2).......(res. in series)
or
i^2 [R1R2/R1+R2 - (R1+R2)] < 0............(1)
= i^2 [R1R2 - (R1+R2)^2/ R1+R2]
= i^2 [-(R1^2 + R2^2 + R1R2] / R1+ R2
since it is less than zero hence =n (1) satisfied
hope my ans is correct plz give me the hat
where there is a will there is a way
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