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[Post New]25 Feb 2007 19:43:12 IST
    Subject: Re:Functions
[Up]
amaron (726)

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Olaaa!! Perrrfect answer. 120  [183 rates]
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2f(sinx) + 21/2f(cosx) = tanx
let x=pi/6
implies
 2f(1/2) + root(2)f(root(3)/2)=1/root(3)      (1)
let x= pi/3
implies
2f(root(3)/2) + root(2)f(1/2)=root(3)          (2)

multiply (1) by root(2) and subtract it from (2) <(2)-(1)>

=

(2-2root(2))f(1/2)=root(3)-root(2)/root(3)

solving, f(1/2) = (3 - 2)/2 3(1- 2)
 
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