IIT JEE , AIEEE Forum - Physics , Mechanics

prateek2292

hey buddy,look.
since the tuning fork which vibrates the wires is same.
therefore,we can equate the two frequencies.
Let the length of two wires be'l'.
Let the tensions in the wire on left be T and on the right be t.
therefore,
after solving u will get T/t=4.
Now,
since the rod is in at rest,therefore we can equate the upward forces to the downward forces.
T+t=mg
4t+t=mg
5t=mg
t=mg/5
T=4mg/5.
Now, write the torque equation taking A as the centre.
Let the block of mass m be hanged at a distance x from A.
mgx-tL=0 (because it is equilibrium)
mgx=tL
mgx=mgL/5
Therefore,

x=L/5.

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