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 Discussion Response Post to:
def.int
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Mar 2008 11:38:27 IST
Accepted Answer [?]
![[Up]](/templates/default/images/icon_up.gif "[Up]")
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its not f(x) | 0
but its f(x) >= 0 (i hv done this question before)
now i think its easy...
since its integral is 0....so either it is symmetrical about x axis and also symmetrical about the line x=6 .... or is 0
(such that half the area lies above x axis and the other half is below according to which the intergal becomes 0...i have done it through graph..)
but its given that f(x) can't be less than 0...so it can't be below x axis...
so f(x) = 0 for all x lying b/w 4 and 8....
so f(6) = 0
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this reply: 5 points
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