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since its a very lengthy procedure so i can tell u the method:
figure with all forces:a ladder-its weight acting downwards thru COM,weight of man( downwards),N1(frm vertical wall),N2 from d ground,friction(f)= N2.
since d ladder should be in horizontal n vertical equilibrium,net torque abt any pt. should be zero
mg+Mg=N2..put the values get d answer
put d condition(f=N1) 4 horizontal equilibrium also,u'll get d answer
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Moderation Team
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