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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Mar 2008 15:58:55 IST
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1. [ x] [4 ] [(cos  ) x-(sin  ) x-cos 2  ]/(x-4) where 0<  <90 by L- hospital's [ x] [4 ] [x(cos  ) x-1-x(sin  ) x-1]/1 =[4(cos  ) 3-4(sin  ) 3]
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