|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Mar 2008 12:48:21 IST
|
|
|
yup there is simple formula....
for any compound=AnBm
n(total no of valence electrons in A)+m(total no valence electrons in B)
= divide the above ans by 8
=the quoteint will be equal to the no of sigma bonds
=the remainer/2 will be = no of lone pairs....
it can be applied to even 3 el;ement compounds and so on...
|
this reply: 4 points
(with 0 
in 2 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
