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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: PROB ON WHEATSTONES'S METER BRIDGE
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pottermania1990 (342)

Blazing goIITian

Olaaa!! Perrrfect answer. 52  [93 rates]

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1) consider resis. 2 be 10 ohms each..balance pt. at 50 cm
   when increased by 10% the left becomes 11 and right resistor remains 10 ohms..
 
now balanced pt is 11/21 * 100 = 52.4 approx
 
increase = (2.4 * 100)/50 = 4.8% to the right

kaushik krishna .R
bits pilani
mech engg
 this reply: 9 points  (with Olaaa!! Perrrfect answer.   in 3 votes )   [?]
 
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