IIT JEE , AIEEE Forum - Physics , Mechanics

Conjurer

Here is my attempt.

Consider a small element rd

where d

is taken with vertical.Force on this element is (dm)gsind

in the direction of its velocity. Now mass of this part is mRd

/L

So total force = mRgsind

d

/L

INtergrating from 0 to L/R we get mRg(1- cos(L/R)/L

So ma = mRg(1-cos(L/R))/L

a= Rg(1- cos(l/R))/L

putting values we get 2/pi (1-cos (1.25pi/2))/1.25 = .69m/s^2 if i have put the value of cos correct.

Is it right?

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