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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Mar 2008 14:28:21 IST
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Normal force acting on the insect N= ( m+ M )g
frictional force = kN = k( m+ M )g
Therefore acceleration a =[ k( m+ M )g ]/m
We know that S=ut + 1/2 at^2
Here initial vel. is zero
Therefore putting S = L we get:-
L=1/2 [ k( m+ M )g ]/m * t^2
or t^2 = 2Lm/ {k( m+M)g}
Hence option (b) is correct
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