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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Mar 2008 19:39:27 IST
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 (cosec2x-2005)/cos2005xdx = - A(x)/B(x)2005
Differentiating with respect to x on both sides
(cosec2x-2005)/cos2005x = 2005 A(x) B'(x)/B2006(x) - A'(x)/B2005(x)
Hence cosec2x/cos2005x - 2005/cos2005x = 2005 A(x) B'(x)/B2006(x) - A'(x)/B2005(x)
Setting A = cotx and B = cosx, LHS = RHS.
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Time wounds all heels |
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