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Discussion Response Post to: answer for this=350

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Priyesh (1601)

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total posts: 1042
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see lets take two boys b1 & b2.

first case

6 apples are to be distributed

if b1 gets 1 apple then b2 will get 5 therefore we write (1,5)

similarly no. of cases are

(0,6);(1,5);(2,4);(3,3);(4,2);(5,1);(6,0)

therefore the total ways are 7 but we have a condition that both boys should get atleast one fruit therefore (0,6) & (6,0) are not valid

therefore total ways of distributing apples = 5

similarly total ways of distributing bananas & oranges is 7 & 10

therefore total ways = 7*5*10 = 350

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