|
|
Since the product of n consecutive int is divisible by n!
Now (n!)! can b written as
(N!)!=1,2,3?.n ---?divisible by n!
(n+1),(n+2)?.2n ---?divisible by n!
(2n+1),(2n+2)?.3n ---?divisible by n!
.
.
.
.
(((n-1)!-1)n+1),,(((n-1)!-1)n+2)?((n-1)!)n ---?divisible by n!
Since we have (n-1)! Rows and each row divisible by n!
Hence proven
How abt that>>>>>>>>>>>
|
Moderation Team
![[Post New]](/templates/default/images/icon_minipost_new.gif){kind=icon}
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
14
