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There are such numbers.
Let us take an example of a four-digit number having digits a, b, c, d. Then the condition is where only 'a' can't take 0 as its value. Hence the required number of solutions will be the coefficient of in
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The coefficient comes out to be .
Similarly repeat the procedure for two-, three-, five-, six-digit numbers. The total number of numbers between 1 and 1000000 is comes out to be
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