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Bipin Dubey (13679)

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1000n/n! = (1000/1).(1000/2).(1000/3)...................(1000/n)
 
For n = 1,2,3...........1000 this value is increasing since every term uptil here is greater than 1.
But for n>1000, 1000/n < 1 and the series would start decreasing since the series is multiplied by numbers less than 1.
 
Hence it attains a maximum value at n = 1000.
 
Best Wishes

Bipin Kumar Dubey Chemical Dept. IIT Kharagpur
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