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[Post New]13 Mar 2008 22:36:23 IST
    Subject: Re:An inequality
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hsbhatt (4985)

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\text{WLOG, assume} \ a\geq b\geq c \\ \\ \text {Hence} \ \frac{a^2}{b^2+c^2} \geq \frac {b^2} {c^2+a^2} \geq \frac {c^2} {a^2+b^2} \\ \\ \text {So, we can use Chebyshev
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