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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Mar 2008 22:44:30 IST
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( a2 + b2 + c2 )/2.( a3 + b3 + c3 )/3= a5 + b5 + c5/5
When a+b+c=0 (proved here http://www.goiit.com/posts/list/algebra-roots-of-polynomial-45973.htm#227419)
=>
(ab+bc+ca)=0
and a+b+c=0 and 3abc=3 =>abc=1
> a,b,c are the roots of the equation:
x^3 -1=0
So we get 1,w+w^2
EDIT: And the answer so is 3.
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