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Discussion Response Post to:
complex numbers
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Algebra
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Author
Message
14 Mar 2008 12:08:15 IST
Subject:
Re:complex numbers
konichiwa2x
(
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Blazing goIITian
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, We have
Now let
Thus
are the roots of
so
So
Therefore
Hence
are the roots of the polynomial
So
Thus since
is divisible by
, we have
Quote from hsbhatt sir:
Hence a
2007
+b
2007
+c
2007
= 1+
+
2
= 0
sir, how is it 0?
Guide to latex:
http://www.goiit.com/posts/list/community-shelf-a-guide-to-latex-48056.htm
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