|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Mar 2008 16:12:19 IST
|
|
|
Rolling motion on an inclined plane : velocity v = [2gs] / [ 1+K2 / R2 ]. acceleration a = gsin / [ 1 + K2 / R2 ]. Where, s = distance of inclined plane K = radius of gyration R = radius of symmetrical body
|
this reply: 10 points
(with 2 
in 2 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|