|
|
|
|
|
 Discussion Response Post to:
limits
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Mar 2008 22:08:34 IST
|
|
|
the limit is actually
lim x->0 { ( 1 - cos (x3 /2) )(1 - cos(x3/4)) } / x12
now apply the formula 1 - cosA = 2sin2 A/2
then you can solve easily.........
|
this reply: 2 points
(with 0 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
