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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Mar 2008 00:19:42 IST
Accepted Answer [?]
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a3cos(B-C)=a2ksinAcos(B-C)
=a2ksin(B+C)cos(B-C)
=a2k(sin2B+sin2C)/2
=a2k(2sinBcosB+2sinCcosC)/2
=a2(b cosC + c cosB)
Similarly,other two terms are b2(c cosC + a cosA) and c2(acosA+bcosB)
adding the three terms we get ab(acosB+bcosA)+bc(bcosC+ccosB)+ca(ccosA+acosC)
=abc+bca+cab
=3abc
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Caution: Radioactive Hazard |
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