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 Discussion Response Post to:
vectors
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| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Mar 2008 18:13:15 IST
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I suppose you are talking about magnitudes.
|A|^2 = |A|^2 + |B|^2 +2|A||B|cos@
and |B|^2 = |A|^2 + |B|^2 +2|A||B|cos@
=> |A| = |B|
So |A|^2 = 2|A|^2 + 2|A|^2cos@
-1/2 = cos@
@ = 2pi/3
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Let us learn to dream, gentlemen, and then perhaps we shall learn the truth.
- August Kekule |
this reply: 2 points
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