Let T denote half life........
T = K [H+](1-n)
when pH = 5 [H+] = 10-5
600 = K 10-5(1-n) .........(1)
when pH = 6 [H+] = 10-6
60 = K 10-6(1-n) ..............(2)
(1) divided by (2) ..... we get
10 = 10-5+5n+6-6n
1-n = 1
so n=0
thus (B) is the right option.........
rate = k[sugar]1[H+]0
Moderation Team
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